Questions
A particle is oscillating along a straight line with time period 6 sec and amplitude ‘A’. Then the time taken by the particle to directly move from to is
detailed solution
Correct option is D
In the phasor diagram, OP=A2 and OQ=A2∴ ∠MOP=cos−1OPOM=cos−112=π4 and ∠NOP=cos−1OQON=cos−112=π3∴ θ=π−π4+π3=5π12∴ Time taken by the reference particle to move from M to N =θω=5π/122π/T=5T24=5×624=1.25sec.Talk to our academic expert!
Similar Questions
Two bodies performing SHM have same amplitude and frequency. Their phases at a certain instant are as shown in the figure. The phase difference between them is
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