Questions
A particle is performing a linear simple harmonic motion. If the acceleration and the corresponding velocity of the particle are a and v respectively, which of the following graphs is correct?
detailed solution
Correct option is C
If a particle performs SHM with angular frequency 'ω' and amplitude 'A' then its displacement from mean position will be equal to x = a sin ωt. If its initial phase is equal to zero, velocity will bev = dxdt=Aω cosωt------(i)and acceleration will bea= dvdt = -Aω2sin(ωt)------(ii)From these equations,cos ωt = vAω, sin ωt = a-Aω2Squaring and adding,v2A2ω2+a2A2ω4 = 1If ‘v’ taken on y-axis and a on x-axis, then it will be an ellipse.Talk to our academic expert!
Similar Questions
The identical springs of constant ‘K’ are connected in series and parallel as shown in figure A mass M is suspended from them. The ratio of their frequencies of vertical oscillations will be
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests