A particle is performing simple harmonic motion. Equation of its motion is x= 5 sin 4t-π6,xbeing the displacement from mean position. Velocity (in ms-1)of the particle at the instant when its displacement is 3, will be:

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2π3

5π6

answer is D.

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Detailed Solution

x= 5 sin 4t-π6When x=3⇒ 35=sin 4t-π6⇒4t-π6=37o velocity =dxdt=5×4 cos4t-π6 =5×4×cos 37o=16 ms-1

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