A particle is performing simple harmonic motion having time period 3s is in phase with another particle which is also undergoing simple harmonic motion at t = 0 . The time period of second particle is T (less than 3s). If they are again in the same phase for the third time after 45s, then the value of T is

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2.8s

2.7s

2.5s

3.2s

answer is C.

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Detailed Solution

Δf=2πT2−2πT1Δt

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