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A particle is performing simple harmonic motion having time period 3s is in phase with another particle which is also undergoing simple harmonic motion at t = 0 . The time period of second particle is T (less than 3s). If they are again in the same phase for the third time after 45s, then the value of T is
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a
2.8s
b
2.7s
c
2.5s
d
3.2s
answer is C.
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Detailed Solution
Δf=2πT2−2πT1Δt
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