Questions
A particle is performing simple harmonic motion. If its velocities are at the displacements from the mean position arc respectively, then its time period is
detailed solution
Correct option is C
Velocity of a particle in SHM v = ωA2-y2v1 = ωA2-y12 ⇒v21 = ω2A2-ω2y21...(i)and v2 = ωA2-y22 ⇒ v22 = ω2A2-ω2y22-----(ii)from equations (i) and (ii), we getv22-v21 = ω2(y12-y22)ω = v22-v21y21-y22 ⇒ T = 2πω = 2πy21-y22v22-v21Talk to our academic expert!
Similar Questions
The identical springs of constant ‘K’ are connected in series and parallel as shown in figure A mass M is suspended from them. The ratio of their frequencies of vertical oscillations will be
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