First slide
Simple hormonic motion
Question

A particle performs harmonic oscillations along a straight line with a period T and amplitude a. The mean velocity of the particle averaged over the time interval during which it travels a distance \frac{a}{2} starting from the extreme positions is

Moderate
Solution

Let the particle start its motion at extreme position.

\large \therefore \,x\, = a\,\cos \omega t

\large V\, = \, \frac{{dx}}{{dt}} = - a\omega \sin \omega t

when \large x\, = \,\frac{a}{2},                 \large \frac{a}{2}\, = \,a\cos \omega t

\large \therefore \omega \tau \, = \,\frac{\pi }{3}

\large \Rightarrow \,\tau \, = \,\frac{T}{6}

\large < v > \, = \,\frac{{\int\limits_0^{\frac{T}{6}} {\left( { - a\omega \sin \omega t} \right)} }}{{\int\limits_0^{\frac{T}{6}} {dt} }}\, = \,\frac{{3a}}{T}

\large \therefore \,Magnitude\, = \,\frac{{3a}}{T}

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