Questions
A particle performs S.H.M. of amplitude A along a straight line. When it is at a distance A from mean position, its kinetic energy gets increased by an amount due to an impulsive force. Then its new 2 amplitude becomes
detailed solution
Correct option is C
Due to impulse, the total energy of the particle becomes:12mω2A2+12mω2A2 = mω2A2Let ‘A’ be the new amplitude.∴ mω2(A')2 = mω2A2⇒A' = A.Talk to our academic expert!
Similar Questions
The identical springs of constant ‘K’ are connected in series and parallel as shown in figure A mass M is suspended from them. The ratio of their frequencies of vertical oscillations will be
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests