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Questions  

A particle performs S.H.M. of amplitude A along a straight line. When it is at a distance 32A from mean position, its kinetic energy gets increased by an amount 122A2 due to an impulsive force. Then its new 2 amplitude becomes
 

a
52A
b
32A
c
A
d
2 A

detailed solution

Correct option is C

Due to impulse, the total energy of the particle becomes:12mω2A2+12mω2A2 = mω2A2Let ‘A’ be the new amplitude.∴ mω2(A')2 = mω2A2⇒A' = A.

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