First slide

Simple hormonic motion

Question

A particle performs SHM with a time period T and amplitude a. The magnitude of average velocity of the particle over the time interval during which it travels a distance $\frac{a}{2}$ from the extreme position is

Moderate

A

$\frac{a}{T}$
B

$\frac{2 a}{T}$
C

$\frac{3 a}{T}$
D

$\frac{a}{2 T}$

Solution

The magnitude of displacement in the given time a interval = $\frac{a}{2}$
Time taken by the particle to cover a distance $\frac{a}{2}$ starting from rest = $\frac{T}{6}$
Hence the magnitude of average velocity over given time interval is = $\frac{\frac{a}{2}}{\frac{T}{6}} = \frac{3 a}{T}$
Hence the correct option is (c).

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App