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Questions  

 A particle performs uniform circular motion with an angular momentum L. If the angular frequency of the particle is doubled and kinetic energy is halved, its angular momentum becomes 

a
4L
b
2L
c
L/2
d
L/4

detailed solution

Correct option is D

We know that, L=mωr2  Further, E=12Lω  or  L=2E/ω ∴ L′=E/22ω=E4ω=L4

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