A particle is projected along an inclined plane as shown in figureg=10m/s2

According the motion of projectile on inclined planeinitial velocity along x axis (Incline plane)=ux=ucos⁡(α−β); acceleration along x axis =ax=−gsin⁡β;initial velocity along y axisuy=usin⁡(α−β); acceleration along y axis=ay=−gcos⁡βα=60∘;β=30∘;α-β=600-30∘=30∘ux=10cos⁡30=10×32=53m/sec, ax=-10sin⁡30=-5m/suy=10sin⁡30=10×12=5m/sec ay=10cos⁡30=−10×32=−53m/sec2 Time to reach from point  0 to point A is time of flight on the inclined planeT=2usin⁡(α−β)gcos⁡βT=2×10sin⁡30∘10×cos⁡30∘ T=23Vx at A=ux+axT=53−5×23=53−103=53m/secVy at A=uy+ayT=5−53×23=−5m/sec∣V→∣ at A=Vx2+Vy2=253+25=1003=103m/sec