Questions
A particle is projected at an angle of 600 above the horizontal with a speed of 10 m/s. After some time the direction of its velocity makes an angle of 30° above the horizontal. The speed of the particle at this instant is
detailed solution
Correct option is D
v cos30° = 10cos60°[As horizontal component of velocity remains unchanged]⇒v=103m/sTalk to our academic expert!
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