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Q.

A particle is projected at an angle of 600 above the horizontal with a speed of 10 m/s. After some time the direction of its velocity makes an angle of 30° above the horizontal. The speed of the particle at this instant is

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a

53m/s

b

53m/s

c

5 m/s

d

103m/s

answer is D.

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Detailed Solution

v cos30° = 10cos60°[As horizontal component of velocity remains unchanged]⇒v=103m/s
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