A particle is projected at an angle of $$600$$ above the horizontal with a speed of $$10ms-1$$.. After sometime the direction of its velocity makes an angle of $$300$$ above the horizontal. The speed of the particle at this instant is:

Question

A particle is projected at an angle of $$600$$  above the horizontal with a speed of  $$10ms-1$$.. After sometime the direction of its velocity makes an angle of $$300$$ above the horizontal. The speed of the particle at this instant is:

Infinity Learn · Accepted Answer

given initial $$velocity=u=10m/s$$; initial θ$$=600$$  ; α$$=300$$ Let v be the velocity of the projectile when it makes an angle   $$300$$  with the Horizontal.  Since horizontal component velocity of projectile remains unchanged $$vcos300=ucos600$$ substitute u $$=10$$, v  $$cos$$  $$300=10cos600$$       $$v32=10$$×$$12$$  $$v=103ms$$−$$1$$

A particle is projected at an angle of $60^{0}$ above the horizontal with a speed of $10 {ms}^{- 1} .$ . After sometime the direction of its velocity makes an angle of $30^{0}$ above the horizontal. The speed of the particle at this instant is:

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A particle is projected at an angle of 600 above the horizontal with a speed of 10ms-1.. After sometime the direction of its velocity makes an angle of 300 above the horizontal. The speed of the particle at this instant is:

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A particle is projected at an angle of $60^{0}$ above the horizontal with a speed of $10 {ms}^{- 1} .$ . After sometime the direction of its velocity makes an angle of $30^{0}$ above the horizontal. The speed of the particle at this instant is: