A particle is projected at an angle of 45° 2m from the foot of a wall, just touches the top of the wall and falls on the ground on the opposite side at a distance 4 m from it. The height of wall is :

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2/3 m

4/3 m

8/3 m

3/4 m

answer is C.

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Detailed Solution

Here θ=45∘ and u2g=6 or u2=6g, also ucos⁡θt=2 or t=2ucos⁡θand y = height of wall, then y=usin⁡θ⋅t+12gt2 =usin⁡θ×2ucos⁡θ+12g×4u2cos2⁡θ or y=83m

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