A particle is projected at an angle of 45° 2m from the foot of a wall, just touches the top of the wall and falls on the ground on the opposite side at a distance 4 m from it. The height of wall is :
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a
2/3 m
b
4/3 m
c
8/3 m
d
3/4 m
answer is C.
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Detailed Solution
Here θ=45∘ and u2g=6 or u2=6g, also ucosθt=2 or t=2ucosθand y = height of wall, then y=usinθ⋅t+12gt2 =usinθ×2ucosθ+12g×4u2cos2θ or y=83m
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A particle is projected at an angle of 45° 2m from the foot of a wall, just touches the top of the wall and falls on the ground on the opposite side at a distance 4 m from it. The height of wall is :