Q.
A particle is projected at an angle of 45o . After 1 sec, it breaks into two equal parts. One part stops and the other part attains the height of 20 m after the breaking of the particle. Find the velocity of projection ( g = 10 m/s2 )
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a
20 m/s
b
202m/s
c
102m/s
d
15 m/s
answer is B.
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Detailed Solution
Vy22g=20m⇒Vy=20 m/s = vertical velocity of the second part.From conservation of momentum m×0+mVy=2mVyoVy0 vertical velocity of particle after one second before breaking of it= Vy2=202=10 m/sBut Vy0=10=uy−gt ⇒uy=10+10×1=20 m/sNow, uy=usin45o⇒u=uysin45o=202 m/s
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