A particle is projected at an angle θ=tan−132 with the inclined plane of angle 30° with horizontal. If α is the angle that its velocity vector makes with vertical at the point of collision (with the inclined plane) if α = 5K°. Find the value of ‘K’.
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answer is 6.
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Detailed Solution
Time of height, T=4Vg7, V=speed of projectionVH=V327V⊥=3V27 Tanα=13, α=30∘.