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Questions  

A particle is projected from the bottom of an inclined plane of inclination 30o. At what angle (from the horizontal) should the particle be projected to get maximum range on the inclined plane:

a
450
b
530
c
760
d
600

detailed solution

Correct option is D

For maximum range:α = π4-θ02 = 450-3002 = 300Angle with horizontal:  θ = α +θ0 = 300+300 = 600

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