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Q.

A particle is projected from the bottom of an inclined plane of inclination 30o. At what angle (from the horizontal) should the particle be projected to get maximum range on the inclined plane:

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a

450

b

530

c

760

d

600

answer is D.

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Detailed Solution

For maximum range:α = π4-θ02 = 450-3002 = 300Angle with horizontal:  θ = α +θ0 = 300+300 = 600
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