A particle is projected from the bottom of an inclined plane of inclination .At what angle α (with the horizontal) should the particle be projected to get the maximum range on the inclined plane.
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
900
b
300
c
450
d
600
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Range =R=u2[sin(2α-β)-sinβ]gcos2β To get maximum range on the inclined plane 2α-β=π2 β =300 ; α=π4+β2 α=π4+302=60∘