Questions
A particle is projected from the bottom of an inclined plane of inclination .At what angle (with the horizontal) should the particle be projected to get the maximum range on the inclined plane.
detailed solution
Correct option is D
Range =R=u2[sin(2α-β)-sinβ]gcos2β To get maximum range on the inclined plane 2α-β=π2 β =300 ; α=π4+β2 α=π4+302=60∘Talk to our academic expert!
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