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Questions  

A particle is projected from the bottom of an inclined plane of inclination  .At what angle α  (with the horizontal) should the particle be projected to get the maximum range on the inclined plane.

a
900
b
300
c
450
d
600

detailed solution

Correct option is D

Range =R=u2[sin(2α-β)-sinβ]gcos2β To get maximum range on the inclined plane 2α-β=π2  β =300 ; α=π4+β2 α=π4+302=60∘

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