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Questions  

A particle is projected from the ground at an angle θ with the horizontal with an initial speed u. Time after which velocity vector of the projectile is perpendicular to the initial velocity.

a
u/gsinθ
b
u/gcosθ
c
2u/gsinθ
d
2utanθ

detailed solution

Correct option is A

Since,   v⊥u or v·u=0or  (u+gt)·u=0or u·u+(g·u)t=0or  u2+gutcos90°+θ=0                  (Angle between u and g is 90° + θ)or    u-gtsinθ=0∴   t=ugsinθ

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