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Q.

A particle is projected from the ground at an angle θ with the horizontal with an initial speed u. Time after which velocity vector of the projectile is perpendicular to the initial velocity.

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a

u/gsinθ

b

u/gcosθ

c

2u/gsinθ

d

2utanθ

answer is A.

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Detailed Solution

Since, v⊥u or v·u=0or (u+gt)·u=0or u·u+(g·u)t=0or u2+gutcos90°+θ=0 (Angle between u and g is 90° + θ)or u-gtsinθ=0∴ t=ugsinθ

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A particle is projected from the ground at an angle θ with the horizontal with an initial speed u. Time after which velocity vector of the projectile is perpendicular to the initial velocity.