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Q.

A particle is projected from ground from point A near the bottom of a wedge. At the same time wedge (sufficiently long) is also moved with same speed towards right as shown, then

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a

Particle can never collide the wedge.

b

Particle will collide the wedge after 2 sec.

c

Maximum height attained by the particle is 11.25 m from the ground.

d

Height of point on the wedge where particle strikes is 10m.

answer is B.

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Detailed Solution

yx=tan30°=103sin600t−12gt2Vwt−103cos600t ⇒13=15−5t103−53 Solving t=2s ymax=1032sin26002g=454=11.25m ystrike=103sin600t−12gt2=103322-12104=10 m
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