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A particle is projected from the ground. If the equation of the trajectory is $y = x - \frac{x^{2}}{2},$ then the time of flight is:

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Correct option is A

The coordinates of point of strike are (R,O)and so 0=R−R22⇒R=2 and R2=1 So, y=x−x22=1−1 22=12 uy22g=y=12 ∴uy=gThus, T=2uyg=2×gg=2g

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A particle is projected from the ground. If the equation of the trajectory is y=x−x22, then the time of flight is:

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Ready to Test Your Skills?

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A particle is projected from the ground. If the equation of the trajectory is $y = x - \frac{x^{2}}{2},$ then the time of flight is: