Questions
A particle is projected from ground making an angle with horizontal. After some time its velocity vector makes an angle of with horizontal at point A, after 1 second the particle is at point B and its velocity vector makes an angle of with horizontal. Then velocity of the particle at A is
detailed solution
Correct option is B
Horizontal component of velocity remains unchanged ∴v1 cos60o=v2 cos30o⇒v2=v13Again v2 sin30o=v1 sin60o-gt⇒v13 x 12=v1 x 32-10 x 1⇒v1=103 m/sTalk to our academic expert!
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