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Q.

A particle is projected from ground making an angle with horizontal. After some time its velocity vector makes an angle of 60o with horizontal at point A, after 1 second the particle is at point B and its velocity vector makes an angle of 30o with horizontal. Then velocity of the particle at A is

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a

203 m/s

b

103 m/s

c

10 m/s

d

20 m/s

answer is B.

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Detailed Solution

Horizontal component of velocity remains unchanged ∴v1 cos60o=v2 cos30o⇒v2=v13Again v2 sin30o=v1 sin60o-gt⇒v13 x 12=v1 x 32-10 x 1⇒v1=103 m/s

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