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Q.

A particle is projected from ground at some angle with the horizontal. Let P be the point at maximum height H. At what height above the point P should the particle beaimed to have range equal to maximum height?

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a

H

b

2H

c

H/2

d

3H

answer is A.

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Detailed Solution

AC=R/2,PC=HWe have to find h = MP.From the previous solution, wo know that if H = R, thentan⁡θ=4Now tanθ=MCAC=MP+PCAC4=h+HR/2⇒4=(h+H)2H⇒ h=H
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