Questions
A particle is projected from ground at some angle with the horizontal. Let P be the point at maximum height H. At what height above the point P should the particle be aimed to have range equal to maximum height?
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Correct option is A
AC=R/2,PC = H , We have to find h = MP. we know that if H = R, then tanθ=4Now tan q = MCAC=MP+PCAC⇒4=h+HR/2⇒h = HSimilar Questions
Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.
Reason : Range of projectile does not depend on the initial velocity of a body.
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