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Q.

A particle is projected from ground at some angle with the horizontal. Let P be the point at maximum height H. At what height above the point P should the particle be aimed to have range equal to maximum height?

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a

H

b

2H

c

H/2

d

3H

answer is A.

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Detailed Solution

AC=R/2,PC = H , We have to find h = MP.  we know that if H = R, then tanθ=4Now tan q = MCAC=MP+PCAC⇒4=h+HR/2⇒h = H
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