A particle is projected from the ground with an initial speed of v at an angle θ with horizontal. The average velocity of the particle between its point of projection and highestpoint of trajectory is
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a
v21+cos2θ
b
v21+2cos2θ
c
v21+3cos2θ
d
vcosθ
answer is C.
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Detailed Solution
Average velocity = Displacement Time =H2+R2/4T/2Putting the required values, we getvav=v21+3cos2θ