A particle is projected from the ground with an initial velocity of 20 m/s at an angle of 30° with horizontal. The magnitude of change in velocity in a time interval from t = 0 to to = 0.5 s is : (g = 10 ms-2)

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5 m/s

2.5 m/s

2 m/s

4 m/s

answer is A.

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Detailed Solution

ux=u cos⁡ θ=20×32=103 vx=103uy=u sin⁡ θ=20×12=10vy=u sin⁡ θ−gt=10−10×0.5=5ms−1⇒Δvy=vy−uy=|5−10|=5ms−1

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