A particle is projected from the ground with an initial velocity of $$20$$ $$m/s$$ at an angle of $$30$$° with horizontal. The magnitude of change in velocity in a time interval from t $$=$$ $$0$$ to to $$=$$ $$0.5$$ s is : (g$$ $$=$$ $$10$$ $$ms-2)

Question

Infinity Learn · Accepted Answer

$$ux=u$$ $$cos$$⁡ θ$$=20$$×$$32=103$$ $$vx=103uy=u$$ $$sin$$⁡ θ$$=20$$×$$12=10vy=u$$ $$sin$$⁡ θ−$$gt=10$$−$$10$$×$$0.5=5ms$$−$$1$$⇒Δ$$vy=vy$$−$$uy=$$|$$5$$−$$10$$|$$=5ms$$−$$1$$

A particle is projected from the ground with an initial velocity of 20 m/s at an angle of 30° with horizontal. The magnitude of change in velocity in a time interval from t = 0 to t_o = 0.5 s is : (g = 10 ms^-2)

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A particle is projected from the ground with an initial velocity of 20 m/s at an angle of 30° with horizontal. The magnitude of change in velocity in a time interval from t = 0 to to = 0.5 s is : (g = 10 ms-2)

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A particle is projected from the ground with an initial velocity of 20 m/s at an angle of 30° with horizontal. The magnitude of change in velocity in a time interval from t = 0 to t_o = 0.5 s is : (g = 10 ms^-2)