A particle A is projected from the ground with an initial velocity of 10 m/s at an angle of 60^o with horizontal as shown in fig. (4). From what height h
should an another particle B be projected horizontally with velocity 5 m/s so that both the particles collide in ground at point C if both are projected simultaneously ?(g = 10 m/s²)

Question

A particle A is projected from the ground with an initial velocity of 10 m/s at an angle of 60^o with horizontal as shown in fig. (4). From what height h

should an another particle B be projected horizontally with velocity 5 m/s so that both the particles collide in ground at point C if both are projected simultaneously ?(g = 10 m/s²)

Infinity Learn · Accepted Answer

The horizontal component of velocity is given byucos⁡θ$$=10$$×$$cos$$⁡$$60$$∘$$=10$$×$$(1/2)=5m/sThis$$ is same as the velocity of B in horizontal direction. Both wilt collide at C if their times of flights are equal, i.e., TA $$=$$ $$TB2usin$$⁡θ$$g=2hg$$ ∵$$h=12gTB2$$∴ $$h2=2u2sin2$$⁡θ$$g=2$$×$$(10)2(3/2)210=15m$$

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