A particle A is projected from the ground with an initial velocity of $$10m/s$$ at an angle of $$600$$ horizontal. From what height should an another particle B be projected horizontally with velocity $$5m/s$$ so that both the particles collide in ground at point C if both are projected simultaneously $$g=10m/s2$$.

Question

A particle A is projected from the ground with an initial velocity of  $$10m/s$$ at an angle of  $$600$$ horizontal. From what height should an another particle B be projected horizontally with velocity $$5m/s$$ so that both the particles collide in ground at point C if both are projected simultaneously  $$g=10m/s2$$.

Infinity Learn · Accepted Answer

Both the particles will meet at C, if their time of flight is the same.  The time Of flight of A is, $$T=2u$$  $$sin$$  θg $$T=2$$×$$10$$×   $$sin$$  $$60010$$ $$T=3second$$ For vertical downward motion of particle B from B to C, we have $$h=12gT2$$         substitute $$T=3second$$ $$h=12$$×$$10$$×$$32$$ $$h=15m=height$$ from where ball B should be horizontally projected

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material