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Questions  

A particle is projected from ground with velocity 20 m/s making an angle of 60o with horizontal. Then angular velocity of the position vector of the particle just before it strikes the ground is 

a
1.5  rad/sec
b
23  rad/sec
c
0.5  rad/sec
d
3  rad/sec

detailed solution

Correct option is C

Range R = u2sin2αgPosition vector r→=AB→where r=AB=R=u2sin2αg∴ ω=component of velocity at B perpendicular to ABAB=usinαR=usinαu2sin2α/g=g2ucosα∴ ω=102×20×cos60orad/s=0.5 rad/sec

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