A particle is projected from the ground with velocity u at angle q with horizontal. The horizontal range, maximum height and time of flight are R, H and T respectively. They are given by, $R= \frac{u^{2} sin 2θ}{g}, H= \frac{u^{2} \sin^{2} θ}{2 g} and T = \frac{2 u \sin θ}{g}$
Now keeping u as fixed q is varied from 30° to 60°. Then:

Question

Infinity Learn · Accepted Answer

Range→      R α $$sin2$$θ  here $$sin2$$θ will first increase till $$450$$ then decreasemaximum height→ H α $$sin2$$θ    here $$sin2$$θ will only increase. time of flight→ T α $$sin$$θ     here $$sin$$θ will only increase.

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A particle is projected from the ground with velocity u at angle q with horizontal. The horizontal range, maximum height and time of flight are R, H and T respectively. They are given by, R=u2sin 2θg, H=u2sin2θ2g and T=2u sin θgNow keeping u as fixed q is varied from 30° to 60°. Then:

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