Question

A particle is projected from ground with velocity $\vec{u} = (40 \hat{i} + 30 \hat{j}) m / s$ . Then range of the projectile is (Take g = 10 m/s²)

Moderate

Solution

Given $\vec{u} = u \cos θ \vec{i} + u \sin θ \vec{j}$ $R = \frac{u^{2} \sin 2 θ}{g} = \frac{2 (usinθ) (ucosθ)}{g} = \frac{2 \times 30 \times 40}{10} m = 240 m$

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