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A particle is projected from ground with velocity $\vec{u} = (40 \hat{i} + 30 \hat{j}) m / s$ . Then range of the projectile is (Take g = 10 m/s²)

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detailed solution

Correct option is C

Given u→ = u cosθi→+u sin θ j→ R=u2sin2θg=2usinθucosθg=2×30×4010m=240 m

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A particle is projected from ground with velocity u→=40i^+30j^m/s. Then range of the projectile is (Take g = 10 m/s2)

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Ready to Test Your Skills?

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A particle is projected from ground with velocity $\vec{u} = (40 \hat{i} + 30 \hat{j}) m / s$ . Then range of the projectile is (Take g = 10 m/s²)