A particle is projected from a horizontal plane with a speed u at some angle. At highest point its velocity is found to be u/2. Then the maximum height attained by the projectile is
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a
u2/4g
b
3u2/4g
c
3u2/8g
d
u2/8g
answer is C.
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Detailed Solution
If α be the angle of projection, Then u cosα=u/2⇒α=60o∴Hmax=u sinα22g=u2sin260o2g=3u28g