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A particle is projected from a horizontal plane with a velocity of at an angle. At the highest point, its velocity is found to be 8 m/s. Its range will be
detailed solution
Correct option is C
The velocity at the highest point =v=v0cosθ0or 8=82cosθ0 or θ0=45∘ Range =v02sin2θ0g=(82)2sin90∘10 64×210=12.8mTalk to our academic expert!
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