A particle is projected from a horizontal plane with a velocity of 82m/s at an angle. At the highest point, its velocity is found to be 8 m/s. Its range will be
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a
6.4 m
b
3.2 m
c
12.8 m
d
4.6 m
answer is C.
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Detailed Solution
The velocity at the highest point =v=v0cosθ0or 8=82cosθ0 or θ0=45∘Range =u02sin2θ0g=(82)2sin90∘1064×210=12.8m
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A particle is projected from a horizontal plane with a velocity of 82m/s at an angle. At the highest point, its velocity is found to be 8 m/s. Its range will be