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Projection Under uniform Acceleration

Question

A particle is projected from a point on ground. It just clears a vertical wall of height h at a distance h from the point of projection and finally hits the ground at a distance 3h from the base of the wall. Then maximum height attained by the projectile is 

Moderate
Solution

y=xtanα1-xR

h=htanα1-h4h

tanα=43

At x=R2=2h, Height (y) attained by the projectile is maximum.

H=ymax=2h.431-2h4h=4h3



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Similar Questions

Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.

Reason : Range of projectile does not depend on the initial velocity of a body.


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