Projection Under uniform Acceleration

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Question

A particle is projected from a point on ground making an angle of $30^{o}$ with horizontal. At time $t_{1} = 2 \sec and t_{2} = 4 \sec$ , it is at the same height h above the ground. Then speed of projection is $(g = 10 m / s^{2})$

Moderate

Solution

Time of flight T= $t_{1} + t_{2}$ = (2+4) sec = 6 sec
Now, $\frac{2 usinα}{g} = T \Rightarrow \frac{2 usin 30^{o}}{10} = 6 \Rightarrow u = 60 m / s$

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