A particle is projected from a point O with a velocity u in a direction making an angle α upward with the horizontal. After some time at point P, it is moving at right angle withits initial direction of projection. The time of flight from O to P is
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a
usinαg
b
ucosecαg
c
utanαg
d
usecαg
answer is B.
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Detailed Solution
when the body projected with initial velocity u→ by making angle a with the horizontal, then after time t, (at point P) its direction is perpendicular to u→. Magnitude of velocity at point P is given by v=ucotαFor vertical motion: Initialvelocity (at point O)=usinαFinal velocity (at point P)=−vcosα=−ucotαcosαTime of flight (from point O to p) = tApplying first equation of motion v= u - gtt−ucotαcosα=usinα−gt∴ t=usinα+cotαcosαg =ugsinαsin2α+cos2α=ucosecαg