The particle A is projected from point P with velocity u along the plane and simultaneously another particle B with velocity v at an angle ‘α’ with vertical. If the particles collide at point Q on the plane, Then
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a
v sinθ−α=u
b
v cosθ−α=u
c
v = u
d
tanθ−α=u
answer is A.
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Detailed Solution
If particles collide at Q, it means their displacement along the plane in same. So their velocity components along the plane should be same.velocity component of particle B along the inclined plane=velocity of particle A⇒ V cos[(90−α)+θ]=u ⇒Vsin(θ−α)=u