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Q.

A particle is projected from a point A with velocity u2 at an angle of 45° with horizontal as shown in figure. It strikes the plane BC at right angles. The velocity of the particle at the time of collision is:

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a

3u2

b

u2

c

2u3

d

u

answer is C.

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Detailed Solution

Let v be the velocity at the time of collision.Then, u2cos⁡45∘=vsin⁡60∘⇒ (u2)12=3v2⇒ v=23u
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