Q.
A particle is projected at600 to the horizontal with an energy E. The kinetic energy and potential energy at the highest point are
see full answer
Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!
Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya
a
(E/2, E/2)
b
(3E4, E4)
c
(E,0)
d
(E4, 3E4)
answer is D.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
Initial K.E., E=12mu2 At the highest point, velocity υ= u cos 600=u2 ∴ K.E. at highest point=12mυ2=12m(u2)2 =14(12mu2)=E4 PE at highest point =mg×u2sin26002g =12mu2(3 /2)2=34E .
Watch 3-min video & get full concept clarity