Questions
A particle is projected horizontally from the top of a tower with velocity 20 m/s. Then the time after which its speed will be . (Take g = 10 )
detailed solution
Correct option is C
After time t, horizontal component of velocity of the particle is, VH = 20 m/s and its vertical component of velocity isVv =0 + gt=10t m/s.∴ VH2+Vv2= 2022⇒ 202 + 10t2=800 ⇒ t=2 sec.Similar Questions
A body of mass 1 kg is moving along positive x-axis with velocity 2 m/s. At t = 0, a constant force, parallel to positive y-axis, starts acting on the body and after 5 sec, speed of the body is found to be 4 m/s. Then work done by the force in 5 sec is
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