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Q.

A particle is projected horizontally from a tower with velocity 10 ms-1. Taking, g = 10 ms-2. Matchthe following two columns at time t = 1 s and mark the correct option from the codes given below.Column.!(A) Horizontal component of velocity(B) Vertical component of velocity(C) Horizontal displacement(D) Vertical displacementColumn.!I(p) 5 SI units(q) 10 SI unit(r) 15 SI unit(s) 20 SI unit

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a

A B C Dp q s r

b

A B C Dq q s p

c

A B C Dq p r s

d

A B C Dq q q p

answer is D.

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Detailed Solution

In horizontal projectile motion,Horizontal component of velocity,ux=u=10 ms-1Vertical component of velocity, uy=gt=10×1=10 ms-1Horizontal displacement =u×t=10×(1)=10 mVertical displacement =12gt2=12×10×(1)2=5 m

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