Question

A particle is projected horizontally from a tower with velocity 10 ms^-1. Taking, g = 10 ms^-2. Match
the following two columns at time t = 1 s and mark the correct option from the codes given below.
Column.!
(A) Horizontal component of velocity
(B) Vertical component of velocity
(C) Horizontal displacement
(D) Vertical displacement
Column.!I
(p) 5 SI units
(q) 10 SI unit
(r) 15 SI unit
(s) 20 SI unit

Moderate

Solution

In horizontal projectile motion,
Horizontal component of velocity,
$u_{x} = u = 10 {ms}^{- 1}$
Vertical component of velocity,
$u_{y} = g t = 10 \times 1 = 10 {ms}^{- 1}$
Horizontal displacement
$= u \times t = 10 \times (1) = 10 m$
Vertical displacement
$= \frac{1}{2} g t^{2} = \frac{1}{2} \times 10 \times (1)^{2} = 5 m$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

SCAN ME