Questions
A particle is projected horizontally from a tower with velocity 10 ms-1. Taking, g = 10 ms-2. Match
the following two columns at time t = 1 s and mark the correct option from the codes given below.
Column.! (A) Horizontal component of velocity (B) Vertical component of velocity (C) Horizontal displacement (D) Vertical displacement | Column.!I (p) 5 SI units (q) 10 SI unit (r) 15 SI unit (s) 20 SI unit |
detailed solution
Correct option is D
In horizontal projectile motion,Horizontal component of velocity,ux=u=10 ms-1Vertical component of velocity, uy=gt=10×1=10 ms-1Horizontal displacement =u×t=10×(1)=10 mVertical displacement =12gt2=12×10×(1)2=5 mTalk to our academic expert!
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