Questions
A particle is projected on to an incline plane of inclination 300 as shown in fig. (g=10m/) then:
detailed solution
Correct option is A
time of flight=T=2usinα−βgcosβ T=(2)(202)sin(450−300)(10)cos300 T=402sin 1510×32=40×1.414×0.255×1.732=1.63secTalk to our academic expert!
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