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Q.

A particle is projected at point A from an inclined plane with inclination angle θ as shown in figure. The magnitude of projection velocity is u→ and its direction is perpendicular to the plane. After some time it passes from point B which is in the same horizontal level of A, with velocity v→ . Then the angle between u→ and v→ will be

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a

θ

b

c

π-2θ

d

90 + θ

answer is C.

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Detailed Solution

α is the required angle.So α = 1800-2θ
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