A particle is projected at point A from an inclined plane with inclination angle $\mathrm{\theta }$ as shown in figure. The magnitude of projection velocity is $\overrightarrow{\mathrm{u}}$ and its direction is perpendicular to the plane. After some time it passes from point B which is in the same horizontal level of A, with velocity $\overrightarrow{\mathrm{v}}$ . Then the angle between $\overrightarrow{\mathrm{u}} \mathrm{and} \overrightarrow{\mathrm{v}}$ will be

• A

  $\mathrm{\theta }$

• B

  2$\mathrm{\theta }$

• C

  $\mathrm{\pi }-2\mathrm{\theta }$

• D

  $90 + \mathrm{\theta }$