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Questions  

A particle is projected at point A from an inclined plane with inclination angle θ as shown in figure. The magnitude of projection velocity is u and its direction is perpendicular to the plane. After some time it passes from point B which is in the same horizontal level of A, with velocity v . Then the angle between u and v will be

a
θ
b
c
π-2θ
d
90 + θ

detailed solution

Correct option is C

α is the required angle.So α = 1800-2θ

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