Q.

A particle is projected under gravity with velocity 2ag from a point at a height h above the level plane at an angle θ to it. The maximum range R on the ground is:

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

(a2+1)h

b

a2h

c

ah

d

2a(a+h)

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Coordinate of point P are (R, - h)Hence R ≤ 2a(a+h)-h = R tan θ- gR22(2ga)(1+tan2θ)or R2tan2θ-4aR tan θ+(R2-4ah) = 0For θ to be real.(4aR2) ≥ 4R2(R2-4ah)or 4a2 ≥ (R2-4ah)or R2 ≤ 4a(a+h)or R2 ≤ 2a(a+h)     Rmax = 2a(a+h)
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon