Questions
A particle is projected upwards with a velocity of 100 m/sec at an angle of 60° with the vertical. Find the time when the particle will move perpendicular to its initial direction, taking g = 10 m/sec2:
detailed solution
Correct option is B
Method I: u→=100cos30°i^+100sin30°j^=503i^+50j^v=u→+g→t=503i^+50j^+−10jt=503i^+50−10tj^if u→⊥v→, then u→.v→=0 so5032+5050−10t=0⇒t=20 second Method II: By v=v+at=u+gtFrom right angled triangleugt=cos60°⇒t=20sTalk to our academic expert!
Similar Questions
Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.
Reason : Range of projectile does not depend on the initial velocity of a body.
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