A particle is projected vertically upward with a velocity of 40m/s. Then the length of path covered by the particle in the last second of its flight is
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a
30 m
b
40 m
c
35 m
d
60 m
answer is C.
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Detailed Solution
From symmetry of motion, we can writeDistance covered in last second of flight 40×1−12×10×(1)2m=35m