First slide

Question on vertical

Question

A particle is projected vertically upward with a velocity of 40m/s. Then the length of path covered by the particle in the last second of its flight is

Easy

A

30 m
B

40 m
C

35 m
D

60 m

Solution

From symmetry of motion, we can write
Distance covered in last second of flight
$40 \times 1 - \frac{1}{2} \times 10 \times {(1)}^{2} m = 35 m$

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