Questions
A particle is projected vertically upward with a velocity of 40m/s. Then the length of path covered by the particle in the last second of its flight is
detailed solution
Correct option is C
From symmetry of motion, we can writeDistance covered in last second of flight 40×1−12×10×(1)2m=35mTalk to our academic expert!
Similar Questions
A boy sees a ball going up and then back down through a window 2.45 m high. If the total time taken by the ball is 1 sec, the height above the window that the ball rises is
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