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Q.

A particle projected vertically upwards attains a maximum height H. If the ratio of the time to attain a height h (h

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a

9h = 5H

b

3h = 4H

c

3h = H

d

4h = H

answer is A.

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Detailed Solution

02−u2=2(−g)H⇒u=2gH ....(i)Time taken to reach H is t2 and Time taken to reach h is t1t1=t23=132Hg∵t1t2=13⇒h=ut1−12gt12⇒h=(2gH)132Hg−12g132Hg2h=2H3-H9hH=59
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