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Q.

A particle is projected vertically upwards from a point A on the ground. It takes time t1 to reach a point B, but it still continues to move up. If it takes further t2 time to reach the ground from point B, then height of point B from the ground is :

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a

12gt1+t22

b

gt1t2

c

18gt1+t22

d

12gt1t2

answer is D.

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Detailed Solution

If after t1 and t2 sec, it is at the same height, then time of flight T=2Ug=t1+t2 U=g2t1+t2At t1, displacement ‘h’h=−Ut1+12gt12Substituting value of ‘U’ h=12g t1t2
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