A particle is projected vertically upwards with a speed of 16 ms-1. After some time, when it again passes through the point of projection, its speed is found to be 8 ms-1. It is known that the work done by air resistance is same during upward and downward motion. Then the maximum height attained by the particle is (take g = 10 ms-2)
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a
8 m
b
4.8 m
c
17.6 m
d
12.8 m
answer is A.
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Detailed Solution
From work-energy theorem, for upward motion 12m(16)2= mgh + W (work done by air resistance) for downward motion,12m(8)2 = mgh – W ⇒ [(16)2 +(8)2] = 2ghor h = 8 m