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Q.

A particle is projected vertically upwards with a speed of 16 ms-1. After some time, when it again passes through the point of projection, its speed is found to be 8 ms-1. It is known that the work done by air resistance is same during upward and downward motion. Then the maximum height attained by the particle is (take g = 10 ms-2)

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a

8 m

b

4.8 m

c

17.6 m

d

12.8 m

answer is A.

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Detailed Solution

From work-energy theorem, for upward motion 12m(16)2= mgh + W (work done by air resistance) for downward motion,12m(8)2  = mgh – W ⇒  [(16)2 +(8)2] = 2ghor  h = 8 m
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